Recent content by brake4country
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Compound interest problem with 3.11% annual rate compounded 3 times yearly
I just used common denominator =)- brake4country
- Post #30
- Forum: Calculus and Beyond Homework Help
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Compound interest problem with 3.11% annual rate compounded 3 times yearly
Articulating and defending my answers: 1. Instantaneous rate as a function of t: FIND THE DERIVATIVE (d/dx a^x=a^x*ln(a). Derivative A'(t)=1050*(3.0311/3)^(3t)*ln(3.0311/3) 2. Total amount invested after 17 years: A(t)=350*(3.0311/3)^3t. A(17)=$592.24. 3. Rate at which the investment IS...- brake4country
- Post #21
- Forum: Calculus and Beyond Homework Help
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Compound interest problem with 3.11% annual rate compounded 3 times yearly
1. 350*(1+(0.0311)/3)*ln(1+(0.0311)/3) 2 and 3. Not sure how to answer these questions.- brake4country
- Thread
- Compound interest Interest Rate Year
- Replies: 36
- Forum: Calculus and Beyond Homework Help
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How much NaOH to add to 0.6 mol acetic acid for max buffering capacity?
Right, because of 1 to 1 ratio. Thank you.- brake4country
- Post #23
- Forum: Biology and Chemistry Homework Help
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How much NaOH to add to 0.6 mol acetic acid for max buffering capacity?
I was confused about this problem because my professor did not do a problem with us like this, but I used an ICE table to figure it out. HOAc + OH- ------> H2O + OAc- I 0.6 x 0 C -x -x...- brake4country
- Post #20
- Forum: Biology and Chemistry Homework Help
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How much NaOH to add to 0.6 mol acetic acid for max buffering capacity?
Conceptually I understand it but I am having difficulty with the calculations.- brake4country
- Post #18
- Forum: Biology and Chemistry Homework Help
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How much NaOH to add to 0.6 mol acetic acid for max buffering capacity?
I am terribly sorry, the answer from the homework was 0.3 moles. That is why I was confused, that 0.2 moles was a typo. So, is the problem that simple? I thought that if we started with 0.6 moles of acid, then the acid would dissociate (not completely) to 0.6 moles of salt and 0.6 moles of...- brake4country
- Post #15
- Forum: Biology and Chemistry Homework Help
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How much NaOH to add to 0.6 mol acetic acid for max buffering capacity?
Yes, I responded to Borek: 0 = log + [salt]/[acid] 1 = [salt]/[acid], which would mean that we would have equal concentrations of salt and acid at maximum buffering capacity. I just don't know how to incorporate NaOH, for which the correct answer is...- brake4country
- Post #13
- Forum: Biology and Chemistry Homework Help
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How much NaOH to add to 0.6 mol acetic acid for max buffering capacity?
Not sure if I was clear. I am new to the HH equation, however, I do know that 4.76 = 4.76 + log [salt]/[acid], which would mean that 0 = log [salt]/[acid]. To reverse the log, raise each side to base 10, which would give me: 10^0 = [salt]/[acid] 1 = [salt]/[acid] This is the point where I...- brake4country
- Post #12
- Forum: Biology and Chemistry Homework Help
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How much NaOH to add to 0.6 mol acetic acid for max buffering capacity?
By adding a base like NaOH.- brake4country
- Post #9
- Forum: Biology and Chemistry Homework Help
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How much NaOH to add to 0.6 mol acetic acid for max buffering capacity?
It reduces the amount of H+ ions, increasing the pH.- brake4country
- Post #7
- Forum: Biology and Chemistry Homework Help
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How much NaOH to add to 0.6 mol acetic acid for max buffering capacity?
Yes. For acetic acid, that would be 4.76. I think my confusion is based on the question. I know that I need to find the ratio of [salt]/[acid] using the HH equation but I don't know what to do with the NaOH.- brake4country
- Post #5
- Forum: Biology and Chemistry Homework Help
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How much NaOH to add to 0.6 mol acetic acid for max buffering capacity?
When the pH = pKa- brake4country
- Post #3
- Forum: Biology and Chemistry Homework Help
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How much NaOH to add to 0.6 mol acetic acid for max buffering capacity?
Homework Statement 0.6 moles of pure acetic acid (no salt) is added to water. How much NaOH would have to be added to get the solution to maximum buffering capacity? Homework Equations pH=pka + log [base]/[acid[ The Attempt at a Solution HAc <---> H+ + Ac- 0.6 mol of H+ 0.6 mol of Ac- All...- brake4country
- Thread
- Capacity
- Replies: 23
- Forum: Biology and Chemistry Homework Help
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What are the probabilities for events A and B in a set of 10 cards?
I need some help in checking my work, especially #4. Problem: You have a set of 10 cards numbered 1-10. You choose a card at random. Event A is choosing a number less than 8. Event B is choosing an even number. Draw a Venn Diagram and calculate each of the following probabilities: 1) P(A)...- brake4country
- Thread
- Diagram sample space Space Venn
- Replies: 3
- Forum: Precalculus Mathematics Homework Help