Recent content by brambleberry

the original equation is 2y^3 + 6(x^2)y - 12x^2 + 6y = 1

Homework Statement 4x - 2xy = 0 how do i solve for EITHER x or y? Homework Equations The Attempt at a Solution i got y = 2 at first but when i plugged it into the original equation to find x it was impossible to get an answer (the x's canceled out)

i don't know how to solve for y using the equation x(y^2) - (x^3)y = 6...i get stuck

Homework Statement dy/dx = [3(x^2)y - y^2] / [2xy - x^3] Find the x-coordinate of each point on the curve where the tangent line is vertical. Homework Equations original equation is x(y^2) - (x^3)y = 6 The Attempt at a Solution i set the denominator of the deriv. to 0, but i...

Homework Statement What is the deriv. of the square root of (xy)? Homework Equations The Attempt at a Solution I used the chain rule: (1/2)(xy)^(-1/2) times (y + x(dy/dx)) i am unsure on how to distribute this correctly

Homework Statement What is the derivative of e^y? i think i am differentiating with respect to x Homework Equations Derivative of y^x is y^x The Attempt at a Solution I don't know if I should use the chain rule or treat it like y^x. When i used the chain rule I got ye^y-1, but then I...

The Attempt at a Solution I took the derivative first and got dy/dx = 2 - 1/x. I then substituted and got the answer 1. I'm confused if I was supposed to use dy/dt at all during this problem, and I don't know if I took the right steps.