Implicit differentitaion and finding coordinates

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Homework Help Overview

The discussion revolves around implicit differentiation and finding coordinates on a curve defined by the equation x(y^2) - (x^3)y = 6. The specific focus is on determining the x-coordinates where the tangent line is vertical, indicated by the condition that the derivative dy/dx has a zero denominator.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss setting the denominator of the derivative to zero to find conditions for vertical tangents. Questions arise about whether to solve for x or y, and how to eliminate one variable. There is also uncertainty about how to manipulate the original equation to find solutions.

Discussion Status

Some participants suggest that it should be straightforward to solve the system of equations given the two equations and two variables. Guidance is offered on using the zero product property to identify potential solutions, but there remains a lack of consensus on the specific steps to take next.

Contextual Notes

Participants express difficulty in manipulating the original equation to isolate variables, indicating potential constraints in their understanding of the algebra involved.

brambleberry
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Homework Statement



dy/dx = [3(x^2)y - y^2] / [2xy - x^3]

Find the x-coordinate of each point on the curve where the tangent line is vertical.

Homework Equations



original equation is x(y^2) - (x^3)y = 6

The Attempt at a Solution



i set the denominator of the deriv. to 0, but i have no idea where to go from there. am i solving for x or y? is there a way i can eliminate one of the variables? do i need to plug anything into the orig. equation?
 
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You have two equations and two variables so it shouldn't be difficult to get what you need. Setting the denominator to zero, you can solve for y. Then using the original equation, you can solve for x.
 
snipez90 said:
You have two equations and two variables so it shouldn't be difficult to get what you need. Setting the denominator to zero, you can solve for y. Then using the original equation, you can solve for x.

i don't know how to solve for y using the equation x(y^2) - (x^3)y = 6...i get stuck
 
Try this: the denominator equals x(2y - x^2), therefore, using the zero product property, the denominator is equal to zero when x = 0 and 2y = x^2. Use the second equation with the original to determine which values of x and y work.
 

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