Recent content by Brett0

Hey everyone. Bit of a random question. So when refrigerant has been fully condensed I understand that it's a liquid, just like a glass of water, albeit under pressure and with no gas above it. When the refrigerant has been superheated it's just a gas, like you would get if you took a sealed...

Hi all, I'm doing some research on vapour absorption cycle machines, mainly water ammonia refrigerators. I've got a few questions. 1. What is the role of the water absorber? ie why do we need the water? 2. In the absorber we have a water ammonia solution. Is the ammonia a gas in the solution...

Hi guys, I've been doing some light reading on hydraulic jumps. For example: So I've been through the basics, super critical to sub ciritcal etc: https://en.wikipedia.org/wiki/Hydraulic_jump So far I understand that the jump occurs at the two points either side of the critical depth, like we...

Brilliant. Along those lines, does that mean that in say, an air-conditioning condenser (Where the fluid is in the same region, ie within the saturation curves) there is actual liquid in the line, as in liquid in a "Pool" as we would commonly view it, together with refrigerant vapour?

I see I see. So we could have two hypothetical vessels that have both reached vapour liquid equilibrium at the same temp and pressure but may have different enthalpy values which will lead them to be at different points on the line?

Indeed that's true. At the equilibrium point described in the hyperphysics link where is that point along the 1-2 line? or am I looking at this wrong.

Hi all., Just hoping to get a better fundamental insight into a few things. If we start with this: http://hyperphysics.phy-astr.gsu.edu/hbase/Kinetic/vappre.html so we have a closed container at a given temperature, then we can find it's saturation pressure. All good so far. In the following...

Another interesting caveat is found in this document: http://www.physics.usu.edu/torre/3700_Spring_2015/Lectures/06.pdf Here we see that for an isobaric H=Q assuming only compressional work is done However in the following pages conditions are given for dF = W regardless of the type of work...

As I understood it if the pressure changes then the PV work required to establish the system in the environment changes, which is what enthalpy is, according to the first few lines of said wikipedia article. I too thought the claim that enthalpy is not pressure dependent was a bit strange.