Recent content by Brock Skywalk

This is great stuff spinnor! thanks bro! i appreciate it! -Skywalker

Hello fellas, anyone know of a website that has practice exams for STRAIGHTS LINES OF MOTION? thanks in advance. -Skywalker

yes sir. i understand now. thank u so much sir. i hope your a sir, lol! i really appreciate it. -Skywalker

Great! so 15m/s downward?

yes it was v = v + a*t. what did i do wrong sir? "a" should be downward, so should i have multiplied by (-10m) thus my answer being 15m/s?

ok. just did another. an object is thrown vertically upward @ 35m/s. taking g = 10m/s^2, the velocity 5 seconds later is? i got 85m/s. i used v = v + a whatta you think?

Thanks Lewando! i really appreciate this. this whole physics thing is a totally different monster. the math is simple is just know how to apply the formulas that i am having trouble with. so could u explain what the variables stand for? a = acceleration t= time but what do the others...

705.6 M. i used the last one.

ok. i got 117.6 M. i used equation #1. what do y'all think?

But i am trying to calculate the distance. what is given is (t) which = 12s and a = 12m/s^2. i am not sure which one to apply.

Ok, i am still confused. what do i do first? thanks again for the reply sir. i appreciate it. -Skywalker

1. AN OBJECT DROPPED FROM A WINDOW OF A TALL BUILDING HITS THE GROUND IN 12.0s. IF ITS ACCELERATION IS 9.80m/s^2, THE HEIGHT OF THE WINDOW ABOVE THE GROUND IS? 2.Not sure again 3. Not sure your assistance is appreciated. -Skywalker

Hello everyone, i am new to this forum so please excuse me if i haven't found the search function. o.k., i am struggling with the following problems. i really don't have cash to get a tutor so i am hoping some of y'all can help a brother out. i am not sure what formulas to use and why. They...