Recent content by BroIIy

i have several notebooks and as we run through the chapters i just write down all notes i can. in the one notebook for chapter 30 (this chapter) i have for 'E' E = N * A * B * W * sin(Wt) Emax = N * A * B * W E = -dIB / dt E = -B*L*Velocity E = I * Resistance now like i said before I am...

thank you Doc Al i found out what i had been doing wrong, i had the entering the wrong numbers and had the wrong Area. here is the solution R1 = .08 Resistance = 6 L = .9 R2 = .04 N = 1950 I1 = 5 I2 = 1.4 T = .3 u_o = 4*pi*10^-7 I3 = E / Resistance E = (Bf - Bo) * A / T Bf =...

here is the work N = 1 Length = .085 Width = .008 Distance = .02 Emax = 1.3E-6 W = 220*pi (this is my symbol for Omega) A = Length * Width u_o = 4 * pi * 10^-7 Emax = N * A * B * W find 'B' B = Emax / ( N * A * W ) solve for 'B' and plug it into... B for a straight...

Hello, i just got done ranting on Q#1 (its in another post, and I am still in a ranting mode) and was about to go to bed for the day, when i figured "well heck i have been working on these 2 questions for 9 hours and have made almost no progress, asking the people in my class for help is like...

1st off, thank you Doc Al for taking the time to try and help me however i don't understand, using my variables is this what you mean? or is there something I am missing? I3 = E / Resistance E = (Bf - Bo) * A / T (Bf = Magnetic field final, && Bo = Magnetic field initial) Bf = .0038117991...

Hello, this is my 1st time asking a question. May I have some assistance? I will just copy and paste the question so that I don't mess up anything Homework Statement A single-turn circular loop of radius 0.08 m and resistance 6 is coaxial with a solenoid of length 90 cm and a radius of...