brotherbobby's latest activity

I should reply to you later when time and the advantage of having done some mathematics first permits. For the case is involved. The...

Due to the coriolis force, the particle acquires a velocity due east (along X) on its way up. For a place in the northern hemisphere...

Yes good question. Sorry I was under the impression that, precisely for my thinking up there, namely that "going up in the northern" is...

Isn't going "up" in the south hemisphere, far as the coriolis force is concerned, the same as going "down" in the northern? (up and down...

Thank you all for your comments. I agree with the corrections to my drawing and with the expression of the coriolis acceleration, namely...

Yes. The Z plane goes vertically up from the place. Y is along the north direction from the place P. Rotation of the earth is in the...

The earth rotates in the Y-Z plane. It's angular velocity vector ##\vec\Omega_0## makes an angle of ##\lambda## with the Y axis and...

Attempt : I start by copying and pasting the diagram for the problem to the right. The rocket marked with R hurls "up" along the z axis...

I copy and paste the relavant paragraphs and images from the text. I might have to do it several times, each time underlining in red...

If you put the value of the tension ##2T = \dfrac{4m_1m_2}{m_1+m_2}g## and subtract it from the force due to gravity ##(m_1+m_2)g##, it...

Gravity is an external force. I suppose what you mean is that if ##m_1## were to accelerate "up" with ##g##, we'd need an agent to apply...

Oh am sorry; you made the correction. However, I find myself struggling with something else. How can the tension be ##T = 2m_1g##...

I failed to understand. Mass ##m_2\; (\rightarrow\infty)## is accelerating downward at ##g##. How is mass ##m_1## accelerating upward...

System : The Atwood's machine is well-known, and drawn alongside, where ##m_2 > m_1##. The (common) acceleration of the masses ##a =...