Ah crap. So 30=60t so 0.5=t
So 120=x/0.5 -> 60= x
And 60=x/(0.5+0.5) -> 60=x
So is my total time = 1hr, drive time =0.5h
With distance being 0.5h (120km/h) = 60km traveled?
Okay so I think, but may be wrong, that Voverall should be 60.0km/h not 120km/h, so my equations would be
(60.0km/h)(xh-0.5h)=(120km/h)(xh)
and
xh=(xh-0.5)+0.5h
I am guessing that the substitution would be to put (xh-0.5h)+0.5h into the equation where xh is.
Therefore...
I have changed the values, and the homework also changes every time I submit a response, I would just like to see an example worked out, so change the values as well if you want!
1. Homework Statement
A person takes a trip heading south with an average velocity of magnitude 120.0 km/h except...