Recent content by bunchedupwalrus

For t < 0 , all I can think of is a qualatative " the field is zero because the intensitity is 0 when the burst of light hasn't been emitted yet " For t >= 0 , I've tried squaring the given E and that let's me say the amplitudes are proportional (with a cos^2 term in the mix) But I feel like...

My bad sorry, it becomes (v+ωR0)^2, have corrected it.

I understand about the unit vectors, I just couldn't figure out how to express them in the forum, sorry about that. a' was meant to be acceleration vector from ma' If I go with -v2/R0 = -µg + 2ωv+ω^2R0 (*All in er direction) I end up with R0µg = (v+ωR0)2 Which gives a vmax of sqrt(R0µg)-2ωR0

It should be negative as it is pulling the person in towards the center?OK, but the directions for the term on the left and the first term on the right are not clearly indicated here. I don't understand sorry. Omega is pointing out of the page, as it is rotating CC, so ez. eTheta is moving CC...

So a is zero, as he is moving at a constant velocity? Or do I use the v2/r as he is changing direction I really appreciate the help, but still feel lost. My new equation is a'= -µg + 2(ωezXvetheta + ωezX(ωezXrer) Using polar coordinates Which solves (if I am computing the crosses correctly) to...

The only tip given by the professor is to use polar coodinates.

So if outwards is positive. Centrifugal would be positive, friction negative, Coriolis I do not know, positive? I don't know what the lefthand a is supposed to represent to be honest, and cannot guess it's sign. We only just went over this is in class, and now the semester is over. Textbook...

Homework Statement A large flat horizontal platform rotates at a constant angular speed ω. A person on the platform walks in a circular path of radius R0 centered on the axis of the platform with a constant linear speed v relative to the platform’s surface. The coefficient of friction between...

Homework Statement *A star on the celestial equator has right ascension of 16h00m00s. At what time of day will this star be at it's highest point, on Febuary 29th 2016. * Homework Equations HA = LST - RA The Attempt at a Solution When LST=RA, it'll be at it's highest point. How do I...