Recent content by bussek327

Diagram is attached.

drawing lines perpendicular to the velocity vectors and noticing that the radius of this curvature lies on the yaxis, you can then connect the exit and entry points with both a straight line and an arc. You need to find the angle at the top of this isosceles triangle in order to be able to find...

Yes r=m*v/q*B but in this case the value of the magnetic field is not given. I understand that the path is an arc from the entry to exit point but do not know how to arrive at an equation for the radius of curvature of this path.

Can someone please explain how to arrive at this equation for R?

I appreciate your patience. V1 is [R1/(R1+R3)]*Vbatt and from that can find I1 from V1/R1. Thank You

Thank you that definitely helps. But I still am having trouble just beginning the problem by finding I1. From what you stated I thought that I would find V1 by (75/202)*12. I've calculated R12eqiv to be 47.15 ohms which gives a current going into both R1 and R2 to be .2545 Amps. I honestly am...

Have read through this thread and still don't understand how to obtain the ratio of resistors OR how to figure out what type of combination R4 is in...Any clarification would be appreciated.