Recent content by BWR

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    Undergrad Different result with kinetic energy and momentum when a bullet hits a target

    I surely want an inertial frame (the ground is good enough). Why did you tell me that?
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    Undergrad Different result with kinetic energy and momentum when a bullet hits a target

    Thank you. Once I estimated the time, how do I calculate the acceleration along the z-axis? should I use ##F = \Delta p / \Delta t##, ##F_z = \Delta p_z / \Delta t##, ##a_z = F_z / (m_b+m_t)##? EDIT Since I know ##\Delta V = v_f - v_{ti}##, I could use ##\Delta V_z / \Delta t = a_z## , right?
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    Undergrad Different result with kinetic energy and momentum when a bullet hits a target

    No, but I found something in the web. Unfortunately I have no idea for its value, but probably I don't need it. Suppose I fire a (small) bullet at a (big) flying target. The bullet slows down upon impact, but the target accelerates with the bullet stuck to it. The target brings the bullet to a...
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    Undergrad Different result with kinetic energy and momentum when a bullet hits a target

    I suppose that the bullet gets stuck in the target and it transfer all its K to the target; is that a contradiction? From my mind. :smile:
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    Undergrad Different result with kinetic energy and momentum when a bullet hits a target

    I'd say that answers my question. Thank you. Does that mean that I should use momentum to get a reasonable result?
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    Undergrad Different result with kinetic energy and momentum when a bullet hits a target

    My English is not good, but here I'm trying to understand 2 things. 1) If ##\frac{1}{2}m_bv_b^2 = \frac{1}{2}m_tv_t^2## and ##m_bv_b = m_tv_t## why the ##v_t## obtained from ##K## is different from that obtained from ##p##? 2) Once I understood a reasonable method to do the calculations, I'm...
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    Undergrad Different result with kinetic energy and momentum when a bullet hits a target

    A bullet hits a target. Assume that all the energy is transferred to the target without destroying it. I want to know the target’s velocity after the impact. bullet: m1= 123 kg, Vx= 2, Vy= 3, Vz= 4. target: m2= 999 kg Calculations using kinetic energy Ecbullet = .5 * m1 * V2 = 1783.5 J...