Recent content by C.S

Thanks for all your help, the maths teacher said it was a last add in the test so that no one could get it all right, no wonder especially in the time given. I will try to meditate all of that and see if I can do it again.

Most people in my class did the same, any ideas though?

I thought ay"+by'+cy=0 gave us ar^2+br+c=0, in my case c=0. I do know how to find particular solutions. I'm going back into class, I will check back later. Thank you for your help.

Yes I do, y0(t)=C1.e-3t+C2 with (C1,C2) →ℝ I believe that's correct.

Hello, I am in need of explinations on how to resolve second degree linear equations with a constant. I had a maths test last saturday and this was the last question : Resolve y"+3y'+2=cos(t) Having almost fallen into the trap of resolving y"+3y'+2y=cos(t), I passed the 2 over by cos(t)...