Recent content by c42

Thank you for responding. So I would take F=3i(x^2 - y^2) + 2j(x+y) plug in y=0, which becomes F = 3i(x^2) + 2j(x) or F = (3x^2)i + (2x)j Then take F dot product ds, with ds = 2i dx. So i would take the integral from 0 to 2 for 6x^2 Which would be 2x^3 from 0 to 2, with an answer of 16 J.

Hi The problem given is that there is a Force vector: F=3i(x^2 - y^2) + 2j(x+y) Then we are given coordinates, where all values are in meters and the magnitude of force is in Newtons. The question asks to calculate the work done in Joules by this force in a displacement along line y...