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Finding dT/t from the pV=nRT Equation
So PdV+dPV=nRdT dT=PdV+dPV/nR dT=2*10-0.3*100/5R dT=-10/5R ... ?- Cadmatic
- Post #3
- Forum: Calculus and Beyond Homework Help
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Finding dT/t from the pV=nRT Equation
Homework Statement pV=nRT dV=10cm^3/min dP=-0,3N/cm^2/min n=5mol V=100cm^3 P=2N/cm^2 where d is change. how does tempperature(T) change( dT/t ) compared to time The Attempt at a Solution No idea- Cadmatic
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- Pv=nrt
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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How Do You Differentiate e^(b*t*ln(t)) + ln(x) with Respect to t?
derivative respect to t <: so: exp(b*t*ln(t))*(b*ln(t)+(b*t*1/t)+1/x ? = e^(b*t*ln(t) * (b*ln(t)+b)+1/x- Cadmatic
- Post #5
- Forum: Calculus and Beyond Homework Help
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How Do You Differentiate e^(b*t*ln(t)) + ln(x) with Respect to t?
nope. It is ln(x)- Cadmatic
- Post #3
- Forum: Calculus and Beyond Homework Help
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How Do You Differentiate e^(b*t*ln(t)) + ln(x) with Respect to t?
D e^(b*t*ln(t)) + ln(x) respect to t my answer: t^(b*t)*(ln(t)*b)+b + 1/x- Cadmatic
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- Chain Chain rule Physics
- Replies: 5
- Forum: Calculus and Beyond Homework Help