Finding dT/t from the pV=nRT Equation

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SUMMARY

The discussion focuses on deriving the change in temperature (dT) over time (t) from the ideal gas law equation pV=nRT. Given the parameters p=2N/cm², V=100cm³, dV=10cm³/min, dP=-0.3N/cm²/min, and n=5mol, the relationship is established through differential calculus. The equation simplifies to dT = (PdV + dPV) / (nR), leading to a specific calculation of dT as -10/5R. This provides a clear method for calculating temperature change in response to volume and pressure changes.

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  • Understanding of the ideal gas law (pV=nRT)
  • Basic knowledge of calculus, specifically differentiation
  • Familiarity with thermodynamic concepts
  • Knowledge of units in the context of gas laws
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  • Learn about the implications of the ideal gas law in thermodynamics
  • Explore the concept of partial derivatives in multivariable calculus
  • Investigate the relationship between pressure, volume, and temperature changes in gases
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Homework Statement



pV=nRT dV=10cm^3/min dP=-0,3N/cm^2/min n=5mol V=100cm^3 P=2N/cm^2 where d is change.
how does tempperature(T) change( dT/t ) compared to time


The Attempt at a Solution



No idea
 
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Consider expanding

d(PV)=d(nRT)

(use the product law on the left side)


I'll help you with the right side :)

d(nRT)=nR(dT)
 
So PdV+dPV=nRdT

dT=PdV+dPV/nR

dT=2*10-0.3*100/5R

dT=-10/5R ... ?
 

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