Finding dT/t from the pV=nRT Equation

[Cadmatic]

Homework Statement

pV=nRT dV=10cm^3/min dP=-0,3N/cm^2/min n=5mol V=100cm^3 P=2N/cm^2 where d is change.
how does tempperature(T) change( dT/t ) compared to time

The Attempt at a Solution

No idea

 

[rock.freak667]

Consider expanding

d(PV)=d(nRT)

(use the product law on the left side)


I'll help you with the right side :)

d(nRT)=nR(dT)

 

[Cadmatic]

So PdV+dPV=nRdT

dT=PdV+dPV/nR

dT=2*10-0.3*100/5R

dT=-10/5R ... ?