Recent content by caesium
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Centripetal force for off-centered cylinders rolling down a curve
My initial attempt: Total Centripetal force on the cylinder would be given by $$\textbf{F}_{net} = mR\omega^2 \textbf{e}_1+mr_{cm}\omega^2 \textbf{e}_2$$ where the vectors e_1 and e_2 have magnitude 1 and point radially outwards (and continuously changing as the cylinder rolls down) as marked in...- caesium
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- Centripetal Centripetal force Curve Cylinders Force Rolling
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- Forum: Advanced Physics Homework Help