Recent content by caitlinbennet
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Undergrad Inverse of s(x)=[1+f(x)]/[1-f(x)]
f(x)?- caitlinbennet
- Post #9
- Forum: Differential Equations
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Undergrad Inverse of s(x)=[1+f(x)]/[1-f(x)]
I found the answer on wolfram alpha, I can invert normal functions but this one has me totally stumped.- caitlinbennet
- Post #7
- Forum: Differential Equations
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Undergrad Inverse of s(x)=[1+f(x)]/[1-f(x)]
really have no idea where to start..- caitlinbennet
- Post #6
- Forum: Differential Equations
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Undergrad Inverse of s(x)=[1+f(x)]/[1-f(x)]
(1+s(x))/1-s(x)?- caitlinbennet
- Post #5
- Forum: Differential Equations
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Undergrad Inverse of s(x)=[1+f(x)]/[1-f(x)]
Is s-1 a composition of f-1.. I'm definitely missing something silly here...- caitlinbennet
- Post #3
- Forum: Differential Equations
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Undergrad Inverse of s(x)=[1+f(x)]/[1-f(x)]
f is a one to one function with inverse f^-1, and we are asked to find the inverse of s(x)=[1+f(x)]/[1-f(x)] My attempts leave me with s^-1(x)= [f^-1(1-x)]/[f^-1(-x-1)] and I don't think this is correct. I can't find any examples of problems like this online.- caitlinbennet
- Thread
- Inverse
- Replies: 9
- Forum: Differential Equations