okay thnx :] are my calculations correct?
.31 = (0)t + .5(9.81)t2
t= .251
then you multiply the time twice for the x direction
x= (11.8)(.251*2) + .5(0)(.251*2)2
x= (11.8)(.502)
x= 5.93
You are using this equation to answer the question, "if an object falls 0.31 m while accelerating under gravity, how long does that take?"
wait I'm confused, the .31 m is my distance?
i thought the question says that the distance is .31m below the height at which it was thrown?
Homework Statement
A dart player throws a dart horizontally at a speed of 11.8 m/s. The dart hits the board 0.31 m below the height from which it was thrown. How far away is the player from the board?
x y
vi= 11.8 vi= 0
a=0 a= 9.81...