Recent content by candyvera

okay thnx :] are my calculations correct? .31 = (0)t + .5(9.81)t2 t= .251 then you multiply the time twice for the x direction x= (11.8)(.251*2) + .5(0)(.251*2)2 x= (11.8)(.502) x= 5.93

You are using this equation to answer the question, "if an object falls 0.31 m while accelerating under gravity, how long does that take?" wait I'm confused, the .31 m is my distance? i thought the question says that the distance is .31m below the height at which it was thrown?

Homework Statement A dart player throws a dart horizontally at a speed of 11.8 m/s. The dart hits the board 0.31 m below the height from which it was thrown. How far away is the player from the board? x y vi= 11.8 vi= 0 a=0 a= 9.81...