Recent content by CarlRozario

Sure thing... New here, so still have to get used to things... In future if you catch me going outta the regular way, let me know... Thanks :-)

N = m*a... . m = mass of the person a = acceleration of the truck... . On a X-Y system... If the truck is approaching along the x-axis from right to left... Tilt your head 90 deg to left... Follow the truck... Now since you're in a non inertial frame... The pseudo force acting is similar to what...

v^2 = u^2 + (2*a*s) The 3rd kinematical equation... . You have the following... v = 0m/s (the final velocity, since your car has stopped) s = 40m (distance traveled) u = initial velocity, (that's what we want to find)... If we only have a (the acceleration, in our case deceleration) . Ff =...