Recent content by cashmoney805

Would you mind providing the solution to the problem? I understand the momentum part: 4=M(1)*V1f + M(2)*V2f And the energy part is M1*V1i2 + M2*V2i2 = M1V1f2 + M2*V2f2 I'm having a hard time doing the math though/figuring out which is easiest to isolate and plug in for.

Oh, well yea. Haha.

Hm, you may be getting confused, thinking the question is asking "in the moment the passenger releases the ball, how far has it moved relative to the bystander." If the question was worded something along the lines of "...how far has the ball moved relative to the bystander when it hits the...

Do you have a formula/any numbers to explain why you're thinking this way?

You can figure out how fast the boy/shoe is moving after 10s. What is the only force acting on his shoe after he drops it?

Homework Statement A car is moving at 25m/s. A passenger, 1.5 m from the ground, can throw a ball at a max speed of 15 m/s and throws the ball out the window as he passes a bystander on the sidewalk. How fast is the ball moving when it leaves the passenger's hand and how far does the ball...

oh is this Kirchoff's rule?

Is the V across the capacitor just 6V? If so I think I'm good. #2 I through the 6ohm resistor is 0, then I through the other two resistors is 18V/20ohms right? #3 I = 6V/18ohms Q= 28 E-6 * 6 #4 (18 * 28E-6) = RC

Homework Statement 1) Determine the current in each resistor and charge on the capacitor after a long time immediately after the switch is closed 2) Determine the current in each resistor and charge on the capacitor after a long time After the switch has been closed for a long time it is...

Ok cool, appreciate it :D

Just one more quick semi-related question: so if you have a square loop in a magnetic field pointing into the page and increasing, the net force on the loop is still 0?

Oh ok. I don't know why, but I had a major brain fart concerning forces pointing in. For some reason I thought they added. Thanks for all the help!

Ok, so for the left and right sides of the top square, 3m part: those forces cancel because they are both pointing out. For the left/right sides of the 4m part: F = (.12)(4)(2)= .96N (pointing in for both sides, so they add?) For the top/bottom: F = (.12)(3)(2) = .72N (up for both of them) So...

Wow, for some reason I'm really confused. The force they're talking about is from the magnetic field, right? You do right hand rule I induced crossed into magnetic field, right?

Since the current is going to be the same everywhere in the loop, don't all the forces just cancel out?