Recent content by cbchapm2
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How Should Angles Be Used in Calculating Tension Forces?
I got the right answer! When I solved the first equation for T2, I dropped the T1 and it threw off everything else too.- cbchapm2
- Post #4
- Forum: Introductory Physics Homework Help
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Finding equilibrium force when two wires pull at 14 degrees below horizontal
Is the degree in the picture the correct one to use in the equation? Since you have to put in the x and y coordinates; it might be 14 degrees BELOW the x-axis on either side, but the angle is measured counter-clockwise from the positive x-axis. So that's why I'm questioning it. I have the...- cbchapm2
- Post #11
- Forum: Introductory Physics Homework Help
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Finding equilibrium force when two wires pull at 14 degrees below horizontal
The sum of the y components would be the 2Tsin(theta). I really just don't know what angle to use for theta.- cbchapm2
- Post #9
- Forum: Introductory Physics Homework Help
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Finding equilibrium force when two wires pull at 14 degrees below horizontal
What angle would you use though? And I'm not really sure for the x direction...is it 0? Or is it 2Tcos(theta)?- cbchapm2
- Post #7
- Forum: Introductory Physics Homework Help
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Finding equilibrium force when two wires pull at 14 degrees below horizontal
I think I got that part... would you find the x and y components using Tcos(theta) and Tsin(theta) for each one? Do you have to do it for each angle? For the angle, would you do counter clockwise from the x-axis?- cbchapm2
- Post #5
- Forum: Introductory Physics Homework Help
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Finding equilibrium force when two wires pull at 14 degrees below horizontal
I don't have a mass or acceleration though...is there a normal force exerted on it?- cbchapm2
- Post #3
- Forum: Introductory Physics Homework Help
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Finding equilibrium force when two wires pull at 14 degrees below horizontal
Homework Statement See the attachment for the diagram and problem: Homework Equations So the magnitude of the tension in the wire is 13.38 N. And each angle is 14 degrees below the x-axis, one on the positive side and one on the negative side. Would I use my Tcos(theta) and...- cbchapm2
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- Force Tension Tension force
- Replies: 10
- Forum: Introductory Physics Homework Help
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How Should Angles Be Used in Calculating Tension Forces?
Homework Statement See attached figure below for problem: I'm designating the "horizontal cable" T1, the "incline cable" T2, and the "vertical cable" T3. Homework Equations I used the following to find x and y components of each force: x comp=Tncos(theta) y comp=Tnsin(theta) The...- cbchapm2
- Thread
- Force Tension Tension force
- Replies: 3
- Forum: Introductory Physics Homework Help
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Finding a plane's weight and horizontal acceleration at takeoff
Got the right answer for both questions! Thanks so much!- cbchapm2
- Post #4
- Forum: Introductory Physics Homework Help
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Finding a plane's weight and horizontal acceleration at takeoff
So you're saying that the 7959.23 N is my weight of the plane? I guess that would make sense, since it's a constant vertical speed (y direction)...- cbchapm2
- Post #3
- Forum: Introductory Physics Homework Help
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Finding a plane's weight and horizontal acceleration at takeoff
Homework Statement On an airplane's takeoff, the combined action of the air around the engines and wings of an airplane exerts a 8240-N force on the plane, directed upward at an angle of 75.0° above the horizontal. The plane rises with constant velocity in the vertical direction while...- cbchapm2
- Thread
- Acceleration Horizontal Weight
- Replies: 3
- Forum: Introductory Physics Homework Help
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Two forces applied to car, direction?
Two forces applied to car, direction?? Homework Statement Here is my given diagram and problem: Homework Equations I'm stuck on finding the direction. I tried using the equation theta=tan^-1(Ay/Ax), and the answer was incorrect. The Attempt at a Solution As you can see, I have...- cbchapm2
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- Applied Car Direction Forces
- Replies: 2
- Forum: Introductory Physics Homework Help
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Projectile Motion problem Phyisics 1
Okay, so I'm trying to find the Vx and Vy for 45*. I just used a value for Vi like you said, 10 m/s. Vx=10m/s(cos 45*)=7.071 Vy=10m/s(sin 45*)=7.071 So now I plug those into the respective X(t) and Y(t) equations? What value do I use for the Xi and Yi of them?- cbchapm2
- Post #24
- Forum: Introductory Physics Homework Help
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Projectile Motion problem Phyisics 1
Why don't you just walk me through the example problem you gave?- cbchapm2
- Post #21
- Forum: Introductory Physics Homework Help
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Projectile Motion problem Phyisics 1
When I was attempting to do this on my own I found this particular page and was still unable to apply it.- cbchapm2
- Post #20
- Forum: Introductory Physics Homework Help