Recent content by ceday

Okay For the Y direction forces, I was using y= -mg+n where n= mg + fsin\theta? for x force , x=-fk + fcos\theta then, x=-\mukn + fcos\theta where again n= mg + fsin\theta? I think the term that I am getting hung up on is the normal force the lawn mower isn't noving up or...

Homework Statement A gardener pushes a 12 kg lawnmower whose handle is tilted up 37 deg above horizontal. The lawnmower's coefficient of rolling friction is 0.15 How much power does the gardener have to supply to push the lawnmower at a constant speed of 1.2 m/s Assume his push is parallel...

ok, i got the answer but i used the net force=2mg i still don't understand why this is so

so would net force in the y direction = zero? if it is zero, i don't think it would be solvable because we don't know the mass wouldnt it be 0=mv2/r

Is the net force in the y direction zero? does the centripetal force = 2mg since normal and gravity both point downward? im lost since this coaster is upside down

Homework Statement The normal force equals the magnitude of the gravitational force as a roller coaster car crosses the top of a 60m diameter loop-the-loop. Homework Equations What is the car's speed at the top? The Attempt at a Solution hello, this problem doesn't give much...

Homework Statement A 1000 kg car pushes a 2000 kg truck that has a dead battery. When the driver steps on the accelerator, the drive wheels of the car push against the ground with a force of 4500N . Rolling friction can be neglected. What is the magnitude of the force of the car on the...

got it! thanks for the tips - chris

net force = tension force of the rope - frictional force?

well i know that Fk = μkmg and f=ma im just not sure what the force should be and if it will give me the right acceleration

Homework Statement A 2.00 kg steel block is at rest on a steel table. A horizontal string pulls on the block. The coefficient of kinetic friction of dry steel on steel is μk=.600 If the string tension is 16.0 N, what is the block's speed after moving 1.30 m? Homework Equations...