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(corrected) PE lost is m*g*deltah = 2kg*9.8*0.17m= 3.332 joules PE gained by spring= 1/2 * k * x* x = 1/2 * 200N/m * 0.17m*0.17m= 2.89 joules So? is that it , friction (spring tension/heat??) just 3.332-2.89= 0.442 joules

Homework Statement A massless spring with force constant k = 200N/m hangs from the ceiling. A 2.0 kg weight is attached to the free end of the spring and released. If the weight falls 17 cm before starting back upwards, how much work is done by friction during its decent? (Note: choose ground...