Recent content by Centrus

In questions like these, it's good to consider one ball at a time: Take one ball, how many possible options are there? Four, since there are four boxes in which it could be placed. Take the second ball, how many possible options are there? Four again. So in total, for the two balls, I have...

As far as I can tell, you have only a single, fairly subtle error. Without meaning to frustrate you, I think it'd be better if you can find it for yourself. I'll give you a couple of hints: 1. The error is in line 7 (where you assign your function value to ydot(2) ) 2. You could easily have...

There is a very useful, analytical means by which the inverse of a matrix can be calculated, using the eigenvalues and eigenvectors of the matrix in question. It even has a name: finding the matrix inverse via eigendecomposition. I imagine it would be in your notes, otherwise it is easily found...

I'd certainly listen to your teacher (since it is he who marks you) in this instance, but I have to say that I have rarely (if ever) seen uncertainties quoted to the same number of significant figures as the measured quantity. For example, 24.012 cm^3 ± 0.0012485 cm^3 looks very strange to...

No worries!

Absolutely! The forces between atoms in the stick are primarily electromagnetic; no different (in nature) to those between electrons in a conductor.

The question asks for the power at tx = 9 μs. I.e. it's asking for an instantaneous power, and so you only need the voltage at that point in time. This you can easily read from the graph to be 700 V. If the voltage V = 0, then the power (at that point in time) P = VI = 0.

Hi, Actually, before I answer your original question, I'll point out that you made a small error in your last step. It appears that you accidentally multiplied the volume by 0.0051993, rather than 0.0051993% (or 0.000051993) to obtain the absolute error in the volume. I.e. you should get...

You are very close! Keep plodding along. The voltage across an inductor is given by: V = L\dfrac{dI}{dt} Now, after rearranging to isolate \dfrac{dI}{dt}, and then integrating, what do you get? Hint: you shouldn't be multiplying the sum of the areas of the rectangles by 820mH. Also...

Hi, To perform element-wise division in Matlab (which I think is what you're trying to do), you must precede the forward slash with a full stop. I.e. replace '/' with './' Matlab performs matrix right division when the operator '/' is used, and I'm not entirely sure what that entails...

Hi, You seem to have calculated the current correctly, so you are on the right track. But to calculate the power, I think you are over-complicating the problem; no integral is necessary. There is a very simple relationship between the power delivered to, and the voltage across a capacitor in...