Recent content by cfc101

h = h0 + volt + 1/2 t^2 so for the first mass at the top h1 = 50 -4.9t^2 mass at bottom h2 = 10t -4.9t^2 To get the center of mass, would i need to add these two equations? Cm = -9.8t^2 + 10t + 50 -----> -4.9t + 5t + 25 I have no idea what to do from here

Well, since this problem only deals with the y axis, the center of mass is 1/3h off the ground (if stationary, using the mass ratio), however, I don't really understand how velocity is factored into all of this

Homework Statement A small ball of mass m is dropped at a height of 50 metres. At the same time, a second ball with twice the mass of the first one is launched at an initial velocity of 10m/s from the ground. Where is the centre of gravity in this system? Homework Equations The...