Recent content by Charlotte Myall

  1. Charlotte Myall

    Can anyone me with this spring question?

    Thank you everyone for your help, especially you Chestermiller, I could not have managed without your help, the answer was indeed 1839.6 N/m
  2. Charlotte Myall

    Can anyone me with this spring question?

    ok, should i square root those two. I have also tried: 0.5kx^2=0.5mv^2+mgh+Fd 0.5kx^2=304.08+4272-4264 0.5kx^2=312.08 *2 kx^2=624.16 so kx=1066.97 kx^2=624.16 equal equations for k, rearrange fro x: x=624.16/1066.97 x=0.58, so k=1839.6, or is this method also wrong
  3. Charlotte Myall

    Can anyone me with this spring question?

    I multiplied the equations by 2 two eliminate the halves
  4. Charlotte Myall

    Can anyone me with this spring question?

    What I did to get that is use the sin rule to get the vertical heigh (vh) which was: vh=sin(21)*8/sin90=2.87 which i then put in the GPE formula to get: GPE=mgh GPE=152.04*9.8*2.87 GPE=4276.28 Which I then inserted into: kx^2=mv^2+mgh-Fd kx^2=608.16+4276.28-4264= 620.44 so kx^2= 620.44...
  5. Charlotte Myall

    Can anyone me with this spring question?

    I think I have calculated it right, by calculating the vertical height, which gave me an answer of 1839.7, can you please tell me if this is the correct answer, or if you got something different
  6. Charlotte Myall

    Can anyone me with this spring question?

    I'm not really sure, how do I calculate that, and is that the only part that I have incorrect.
  7. Charlotte Myall

    Can anyone me with this spring question?

    From my calculations I have got: kx=1066.97 kx^2=14336.72 Which if I then both equal to k, I get 1066.97/x=14336.72/x^2 Which then I multiply with x, to eliminate one side, and then rearrange to get; x=14336.72/1066.97 x=13.44 Which is the wrong answer as x cannot be higher than 8, if 8...
  8. Charlotte Myall

    Can anyone me with this spring question?

    Or what value it is closer to ou of; 1871 1873 or is it neither of those two, and it is my decimal figures which are wrong
  9. Charlotte Myall

    Can anyone me with this spring question?

    can you please tell me, what you got, and how. I know you are probably busy, but I would really appreciate it if you could help me some more.
  10. Charlotte Myall

    Can anyone me with this spring question?

    Ok, I think I know what you are trying to tell me, and I think I may have done the method you are trying to tell me, but I always end up stuck in the last part, with the rearranging: force on spring= force on slope+friction F=kx=mgsin(theta)+friction F=1066.97 Elastic spring energy= kinetic...
  11. Charlotte Myall

    Can anyone me with this spring question?

    Can you please tell me what I am missing, I think one of them is gravitational potential energy, but I'm not sure about the other
  12. Charlotte Myall

    Can anyone me with this spring question?

    Ok, thank you for helping me first of all. Basically what I am trying to do is figure out the spring constant by obtaining the force, and the distance the spring moved and the force exerted on the spring First I have tried finding the force on the spring by calculating force on the slope, as...
  13. Charlotte Myall

    Can anyone me with this spring question?

    I am not looking for an answer, just a method that gives me a result close to 1871.88. I have tried this for hours and when I entered that value it says it is wrong but by a small amount. Please, can someone help me as soon as possible, the assignment is due at 9pm tonight. 1. Homework...
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