Recent content by chevymechanic

"roots" command in MATLAB Hey everyone. I'm a new user to Matlab. I must say, it's an awesome program, but not user-friendly at all. I'm having trouble trying to use the "roots" functon. Here's what part b of my problem states: "Use the roots function to compute the time when the aircraft...

Haha. DUH on my part! I figured it was something obvious. I just squared both, divided that by 1470, plugged that answer into the inverse tangent, and voila...11 degrees. Thanks. My mind just drew a blank on that one.

Homework Statement Hello. I'm trying to solve this equation: 16.9038=\sqrt{1470tan\theta} Homework Equations The Attempt at a Solution I just need to know what theta is. It's been a while since I've calculated something like this and just need someone to show me the steps...

Wouldn't the total mass be 5M? The block hanging from the left side of the table is M, middle block is 2M, and the block hanging from the right side is also 2M. I guess it would still mean that a mass of 1M is accelerating the masses though. I don't understand why I would have to calculate the...

Homework Statement When three blocks are released from rest, they accelerate with a magnitude of 0.500 m/s2. Block 1 has mass M, block 2 has 2M, and block 3 has 2M. What is the coefficient of kinetic friction between block 2 and the table? (The blocks are arranged with block 1 hanging from...

Haha! Success! I've figured it out. I knew it had to be something simple. I just needed someone to clear things up for me. Thanks a million!

sin(-37.0)= -.601815 But when I try to solve -730=V0(-.601815)(5.00)-122.5 I get -730=V0-125.509. I just don't see how to go from that to the answer V0=202 m/s

Homework Statement Here's the equation I have: 0-730=V0sin(-37.0)(5.00)-(1/2)(9.8m/s2)(5.00)2 Homework Equations The Attempt at a Solution I know the answer is 202 m/s. I just can't figure out how to get there. I've reduced it to: -730=(V0sin(-37.0))(5.00)-122.5 The...

Well, I got the question wrong. The computer is VERY picky about what answer or format (mine was wrong) that you put in it. It was looking for: (2d+g(\Deltat2))/(2g\Deltat) ^^^That's supposed to be Delta t ^2nd power. I still don't have the concept of the Constant Acceleration formulas...

If I were to write an expression for d, which would be a combination of d1 and d2, that would leave me with: d = (1/2)g(t-\Delta)2+(1/2)gt2 Would I then set d=0 and use the quadratic formula to solve for t? I have something similar in my notes, but this is where I usually get lost in...

Hmm. I know that \Deltat would be the change in time, which is final-initial. So I would have to work "t-0" into the equation somehow. d2 = (1/2)g(t-0)2...? I don't think that's right because "t-0" would leave me with just "t" and would be the same as the first equation...

I'm going to say it's: x-x0=v0t+(1/2)at2 The g constant would sub in for a and d would sub in for x-x0 correct? Then would V0 be 0 because the objects start from rest? Then the only variable left is "t", which is what I need to find.

Homework Statement Two diamonds begin a free fall from rest from the same height, a time "delta t" apart. How long after the first diamond begins to fall will the two diamonds be a distance "d" apart? Give your answer in terms of the variables given and "g". ( Solve for t= ) Homework...