Recent content by chickymd

Thanks for the help (and for catching my typo).

Do I just integrate both sides from 1 to 2? ∫(from 1 to 2) -κδP=∫(from 1 to 2) δln(V) -κ(P2-P1)=ln(V2)-ln(V1)=ln(V2/V1) V2/V1=e^(-κ(P2-P1)) V2=V1=e^(-κ(P2-P1)) Is this correct?

-κV=δV/δP -κδP=δV/V=δln(V) I can get this far, but I don't know how to solve it now.

Yes, I'm following. Does that mean dV/V=dln(V)?

It's 1/x

No, I haven't.

No, I haven't taken differential equations.

δV/δP=-κV I'm not sure what to do now.

Homework Statement When pressure is applied to a liquid, its volume decreases. Assuming that the isothermal compressibility κ=-1/V(δV/δP) is independent of pressure, derive an expression for the volume as a function of pressure. Homework Equations The Attempt at a Solution I don't...