Recent content by chiddler

Because they can move past each other more easily. Similar to a faster speed of a spacecraft being able to overcome gravitational pull.

I'd expect that since they carry more kinetic energy, they are more fluid. Thanks!

Ok I'm sorry about missing the details initially. P=IV, voltage increases 100x so I must necessarily decrease 100x in order to keep power constant. Current decreased in wire and therefore voltage also decreased proportionally. P = IV = (I *1/100) * (V * 1/100) = 1/10000 or the equation that...

edit: hold on I'm trying to prove to myself why current decreased.

Voltage is increasing, power is constant. Therefore, current must decrease inversely proportional to the V increase. Yes? But if P=IV, then P=(I/100)*(100V) = P. It looks like it works with the equation that you used, P=I^2/R, but how would I make it work with P=IV? Seems very unintuitive to...

i'm glad. this has bothered me for a long time. thank you very much for the very helpful responses.

This makes perfect sense! thank you.

Homework Statement If you step up the voltage in a wire by a factor of 100, how is heat affected? A. No change B. Heat loss increases by a factor of 10000 C. Heat loss decreases by a factor of 10000 D. Not enough information to tell Answer: "C, heat loss decreases by a factor of 10000...

appreciate it. I'm not very comfortable in a calculus based approach as my physics was only algebra based. So could you please accommodate me in your response? (ie, more conceptual, please) I didn't ask immediately because I didn't think this question gathered enough interest for follow up...

thanks very much for the excellent response.

Homework Statement I'm trying to understand two things: 1. How internal energy is distinct from kinetic and potential energy 2. The difference between internal energy and enthalpy. Homework Equations enthalpy ΔH = ΔU + PΔV internal energy ΔU = Q + W = Q - PΔV The Attempt at a Solution I...

My friend provided a helpful response: Because the particle is constrained to the bar. Magnetic forces do no work on particles because the force on the particle is always perpendicular to the field. When the particle is trapped in a bar and is forced to move in one direction only, the magnetic...

Homework Statement Magnetic forces do no work because all the force is perpendicular to movement. A bar is moving in a Bfield. "How much work is done on an electron moving across the bar?" Why is there work in this case? Homework Equations F = qvBsin(θ) W = Fd = qvBd*sin(θ)...

hey and thanks for the response! that's a nice way to put it. C is clearly the most springy. Now I'm trying to translate this concept to generating electrostatic potential energy. The reason there exists this potential energy, besides the obvious repulsion, is that negative charges...

Homework Statement Homework Equations PE = -Fdcos(theta) PE = -(qE)dcos(theta) PE= -pdcos(theta) or PE = - pd since all the angles here are nice. where p is dipole The Attempt at a Solution :( beyond trying to find what looks like the answer, I'm not sure many thanks!