Recent content by ChiHawksFan

Yep, I did write something down wrong. It is supposed to be 'a' in the denominator. Thanks for the help Sammy, and sorry for the error!

I tried something else, and I think I am a little closer to a solution. τ = Fdsinθ, τ = Iα, α = a/r, d = r = the radius of the spool, F = mhg - mha Fr = Iα Fr = I(a/r) Fr2 = Ia (Fr2/a) = I I = [r2(mhg - mha)]/a This solution is closer, but instead of 'α' in the denominator, there is just...

Actually, I did mean for τ to be torque in each equation. I realize now that I totally forgot to add tension into my ∑Fy equation. I will try that and see if I can get a better result. Thanks for the help!

Homework Statement Hi all, I just had a quick question regarding a problem that I have to write a lab report on. The problem involves solving for the moment of inertia of a system that involves a pulley with a hanging mass attached to a spool that turns a flywheel. The solution is supposed to...

Mass of Cannon = 500 lbs = 226.8 kg, Mass of Projectile = 20 lbs = 9.1 kg, vpi (Initial muzzle velocity) = 400 m/s First, I calculated the KE of the projectile in the first situation in which the cannon remains stationary. KE = (1/2)mv2 --------> KE = (1/2)(9.1)(400)2 -------> KE = 728,000 J...

Actually, I just solved this problem, but I will show my solution incase someone else might find this helpful.

Homework Statement A cannon that weighs 500 lbs shoots a cannonball horizontally that weighs 20 lbs at 400 m/s while mounted in place so that it does not move. If the same cannon and cannonball are shot in the same way with the cannon mounted on wheels allowing it to recoil, what is the new...