Recent content by Chuck Norris

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    Does Potential Energy Equal Kinetic Energy at the Bottom of a Hill?

    Ok thanks that is what I thought. In the original question is says if friction can be ignored. So I believe that we are acting as if there is no friction involved. Thanks for your help.
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    Does Potential Energy Equal Kinetic Energy at the Bottom of a Hill?

    Homework Statement Say your potential energy at the top of a hill is 7,350 J. At the bottom of the hill wouldn't the kinetic energy then be 7,350 J? Homework Equations N/A The Attempt at a Solution N/A
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    Grams of H2 react with 28.0 grams of N2

    Homework Statement how many grams of H2 are needed to react with 28.0 grams of N2? Homework Equations The Attempt at a Solution I believe the answer to be 14 grams or 6 grams. I keep going back and forth between the 2. Any help would be greatly appreciated, thanks!
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    Vertical Component of a ball rolling off table

    maybe?
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    Vertical Component of a ball rolling off table

    The answer is just 5 m/s.
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    Vertical Component of a ball rolling off table

    unless the initial horizontal velocity is just zero...since there are no forces changing it
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    Vertical Component of a ball rolling off table

    The initial horizontal velocity is 5 m/s correct? I don't believe any forces are acting to change it...
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    Vertical Component of a ball rolling off table

    Haha wait so is the answer just 5 m/s? Because horizontal velocity doesn't change?
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    Vertical Component of a ball rolling off table

    Would I just use the same formula as I used with the vertical component but plug in the 5m/s as the initial velocity instead of 0?
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    Vertical Component of a ball rolling off table

    nevermind i see that I'm looking for velocity again yet i went back to answering in distance
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    Vertical Component of a ball rolling off table

    The intial horizontal velocity is 5 m/s when it rolls off the table. So would it be: d=Vot D= (5m/s)(0.6s) d= 3m?
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    Vertical Component of a ball rolling off table

    Awesome! Thank you so much. Now for the second part, what is the horizontal componenet ofthe ball's velocity just before it hits the floor? Would I use the formula d(horiziontal)=Vot? Now I'm confused because if I use that formula and plug in the initial velocity of 0 obviously I'm going...
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    Vertical Component of a ball rolling off table

    V = Vo + at V= 0 + (10 m/s^2)(0.6s) V= 6 m/s I'm assuming since there is not a initial velocity given in the problem that the initial velocity is assumed to be 0. Sorry for all the dumb questions, physics has just been rough for me so far. Thanks for all your help so far.
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    Vertical Component of a ball rolling off table

    V = V0 + at V= 5 m/s + (10m/s^2)(0.6s) V= 5.6 m/s? I'm sure this is the wrong formula also.
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    Vertical Component of a ball rolling off table

    So then am I using the wrong formula all together?
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