chwala's latest activity

Okay, in my understanding, the 7 portraits create 8 gaps. Of these, 2 gaps are unavailable because they are immediately before and after...

Yes, the positions of the modern paintings relative to the ends of the arrangement are automatically accounted for in my counting. In...

@anuttarasammyak man! You're throwing punch after punch! Cheers mate.

An improved apprach of counting the possibilities Let us add one more item say J, meaning joint, to make a circle from a line with it...

You forgot to multiply by 6 (Case 1 + Case 2 = 81,285,120). That is an elegant solution - was it inspired by @PeroK's (or...

Case 1 Treat the two modern paintings as one block, leaving 7 units to arrange: 5 landscapes, 1 modern block, and 1 abstract block...

Will fix that...

$$N(x,y,z)=\max(x-1,0)+\max(y-2,0)+\max(z-1,0)$$ $$=\max(x-1,0)-x+\max(y-2,0)-y+\max(z-1,0)-z+10$$ $$=10-\min(x,1)-\min(y,2)-\min(z,1)$$...

Amended by including ##6## We consider two cases - what i would call gap method. Case 1 - Two modern are adjacent ... and considering...

After the idea the problem is reduced to 12 items, i.e., 4 portraits, 5 landscapes, 1 abstract paintings group, and 2 modern art pieces...

Yes, 487,710,720 verified by computation.

The answer I got was ##(224 \times 9!) \times 6##. Given that the total number of permutations is ##12!\times 6##, that gives the...

Identifying the 7 categories first is a good start.

Does nobody care why a music curator is trying to hang these rare paintings? 🤔

... noted @PeroK . Let me look at it with your points in mind.