Recent content by clayton1975mg

Hi. I studied this question in my vocation and I concludes this not possible. Look: conditions: 1) log(a+b)= log(a) $ log(b) 2) ln(a+b)= ln(a) $ ln(b) 3) a=b=1 consequences 1) log(1+1)= log (1) $ log (1) 2) ln(1+1)= ln (1) $ ln (1) so 1) log (2) = 0 $ 0 2) ln(2) = 0...