Recent content by cleo0724

A 21.0 kg box is released on a 36.0° incline and accelerates down the incline at 0.271 m/s2. Find the friction force impeding its motion. F=mg*cos(36) F=21(9.8)*cos(36) F=205.8*.809 F=166.495 I'm not sure what I'm doing wrong. Please help