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Projectile, max height half the range, find angle
I was able to figure it out but thanks!- click0420
- Post #3
- Forum: Introductory Physics Homework Help
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C
Projectile, max height half the range, find angle
Homework Statement find the angle of the projection for which the maximum height is equal to half of the range Homework Equations vertical: h =(vsinθ)t-0.5(g)(t^2) horizontal: 2h =(vcosθ)t The Attempt at a Solution i know you set both equations equal to each other (vsinθ)t...- click0420
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- Angle Height Max Max height Projectile Range
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- Forum: Introductory Physics Homework Help