Recent content by CLouD8521
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What is the integral of sin(x^2) dx?
I have a problem. Isn't: \left[cos(u)\right]_0^{625} = cos(625)-cos(0) = (-0.984387)-(1)=-1.984387 Therefore; \frac{1}{4}\int_0^{625} sin(u) du = -\frac{1}{4}(-1.984387)= 0.496097- CLouD8521
- Post #24
- Forum: Calculus and Beyond Homework Help