Recent content by clueles

please help me with this! f(x)=3x^2+7x=5. find the solution of f(x)==0(mod m) for m=23 m=25 the only thing i have done so far is completed the square

no i haven't

find the number of solutions in z103 x^2==22(mod103)

Yes we are up to that part but I'm not sure how to even start it. Do we need to say for all \epsilon> there exists a n,m /geqN such that abs(Snk-Smk)<E?

college level for a real analysis class

is that how you would write a formal proof or would you the for any epsilon>0 there exists an n in i such that abs(sm-sn)<epsilon

I need help on trying to prove that every subsequence of a cauchy sequence is a cauchy sequence

to use the chinese remainder theorem wouldn't you have to rewrite the equation s for the x's as x==-3(mod5) x==-2(mod6) x==-3(mod7) so then we can rewrite it using the q's. and once we figure out what the general form of it the x would be the remainder of it

Question again how can you use the chinese remainder theorem if you have an x and y and you want to do it simulatenously?

Thank you for answering my question. I just need some clarification though. When you have the x + 3 == 0 (mod 6), y + 1 == 0 (mod 6). do you solve the congruence x + 3 == 0(mod6) and then you solve the second y+1 == 0(mod6) and once you do you subsitute the remainder into the n = 2^x *...

fi have no idea what to do and i tried posting it on another forum and nobody replied so please help me! thank you so much! find a positive integer n so that 40n is a fifth power (of an integer) 500n is a sixth power, and 200n is a seventh power, or explain why it is impossible to do so...

i'm sorry i really don't follow your explanation. my guess that you have to divide the factorizations and that could possibly give you the answer

a = 238000 = 2^4 x 5^3 x 7 x 17 and b = 299880 = 2^3 x 3^2 x 5 x 7^2 x 17 is there an integer n so that a divides b^n if so what is the smallest possibility for n

can you explain it again i'm still confused about it. how do you get the -1. I'm sorry would you be able to explain it a different way?

I have 2 questions. 1)what is the remainder with 100! is divided by 103? explain your answer 2)a = 238000 = 2^4 x 5^3 x 7 x 17 and b=299880 = 2^3 x 3^2 x 5 7^2 17. Is there an integer so that a divides b^n? if so what is the smallest possibility for n? the first one i have no...