Recent content by clueless_rosh

ok thnx.. :)

ok from what i can guess potential energy = mgrcos(theta) - 0.5k*(r^2) kinetic energy = 0.5(m(dr/dt)^2) + 0.5(mr^2)(dtheta/dt)^2

sorry..the image can be seen here :) http://img20.imageshack.us/i/imagenhv.png/

lagrangeian problem... Homework Statement in a spring pendulum system the spring is initially in equilibrium at upright position with theta = 0 and elongation (mg)/k, (k is spring constant). total length of spring in equilibrium condition is a with respect to which we define additional...