Okay, so I've started from scratch and this is what I've got. Hopefully, it looks correct!
Volume of cube = .000006m or .0006cm
Density ρ of cube = 8.8 g/cmcm3 or 8800kg/m^3
Density ρ of milk = 1.03 g/cm^3 or 1030 kg/m^3
T=?
scale +Fb-mg=0
T + ρgVdisp - mg=0
T+ 0.060564-.51744=0
T=.457N
Fb=...
This is what I did:
Fb (buoyancy) = ρgVdisp
Fb=1.03g/cm^3(9.8)(6cm)
Fb=60.564
mg=
ρ=m/v ⇒ m=ρv
m= 8.8(6cm)
m=52.8
Then 52.8(9.8) = 517.44
This doesn't look correct either though, so I'm not sure where to go...
I understand what y'all are saying about my units, but I'm just not sure where...
This is what I did:
Fb (buoyancy) = ρgVdisp
Fb=1.03g/cm^3(9.8)(6cm)
Fb=60.564
mg=
ρ=m/v ⇒ m=ρv
m= 8.8(6cm)
m=52.8
Then 52.8(9.8) = 517.44
This doesn't look correct either though, so I'm not sure where to go...
I understand what y'all are saying about my units, but I'm just not sure...
Homework Statement
A 0.02 m x 0.01 x 0.03 block of copper (density = 8.8 g/cm3) is suspended submerged in milk (density = 1.03 g.cm3) by a string. How much tension is in the string?
Homework EquationsThe Attempt at a Solution
My initial thought for an equation was:
T+Fb(buoyancy)-mg=0
T+...