Recent content by Col Musstard

i can't seem to get this problem to work, it seems to repeat itself

well, it is arctan x so i need to do some recalculating now

Homework Statement integral tan-1x dx i am supposed to integrate this by parts Homework Equations The Attempt at a Solution integral tan-1x dx = integral cosx/sinx dx u=cos x, du=-sin x dx v=ln sin x, dv= sin-1x dx integral cosx/sinx dx= cosx ln(sinx) - integral[ ln(sinx)(-sinx) dx] is...

so u=cos^-1x. therefore du=-1/sqrt[1-x^2] dx is this correct so far? I got -[[cos^-1x]^2]/2 +c hope its right, thanks for the help

that is -1/sqrt[1-x^2] isn't it

Homework Statement evaluate using substitution Integral [cos^-1 x]/sqrt[1-x^2] dx Homework Equations The Attempt at a Solution I am just starting with integration and I am getting frustrated with this problem. If someone could show me how to setup and start this problem so I could...