Recent content by Col Musstard
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Integrating by Parts: tan-1x dx
i can't seem to get this problem to work, it seems to repeat itself- Col Musstard
- Post #4
- Forum: Calculus and Beyond Homework Help
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Integrating by Parts: tan-1x dx
well, it is arctan x so i need to do some recalculating now- Col Musstard
- Post #3
- Forum: Calculus and Beyond Homework Help
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Integrating by Parts: tan-1x dx
Homework Statement integral tan-1x dx i am supposed to integrate this by parts Homework Equations The Attempt at a Solution integral tan-1x dx = integral cosx/sinx dx u=cos x, du=-sin x dx v=ln sin x, dv= sin-1x dx integral cosx/sinx dx= cosx ln(sinx) - integral[ ln(sinx)(-sinx) dx] is...- Col Musstard
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- Integrate parts
- Replies: 4
- Forum: Calculus and Beyond Homework Help
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Evaluate integral using substitution
so u=cos^-1x. therefore du=-1/sqrt[1-x^2] dx is this correct so far? I got -[[cos^-1x]^2]/2 +c hope its right, thanks for the help- Col Musstard
- Post #5
- Forum: Calculus and Beyond Homework Help
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Evaluate integral using substitution
that is -1/sqrt[1-x^2] isn't it- Col Musstard
- Post #3
- Forum: Calculus and Beyond Homework Help
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Evaluate integral using substitution
Homework Statement evaluate using substitution Integral [cos^-1 x]/sqrt[1-x^2] dx Homework Equations The Attempt at a Solution I am just starting with integration and I am getting frustrated with this problem. If someone could show me how to setup and start this problem so I could...- Col Musstard
- Thread
- Integral Substitution
- Replies: 5
- Forum: Calculus and Beyond Homework Help