The magnetic field midway between two long straight parallel vertical conductors (due to the current flowing through them)is twice the strength of the field due to only one wire at the same point how far to the right of the right most wire will the strength of the field be 1/10 of the strength...
the field inside a conductor is zero therefore
A. the potential inside the conductor is zero
B. the potential cannot be zero
C. The potential inside the conductor is the same as the potential just outside the conductor (on the surface)
D. the potential inside the conductor cannot be defined...
Hi,
please anyone hlep me this statement. I am doing online quiz. one question I am getting problem. so, i want to know this statement true or false...
The electric field is perpendicular to the electrostatic force ( T or F)
Thansk!.
I am having some trouble following what you wrote ("only action also"??)
When it is horizontal, what is the net force along x? (I know it is Fc but forget about Fc, this is not a fundamental force. You should just think about tension and weight). What is the net force along y?
What is the...
when the stopper is rotaing FC and Fs aree actiong on the stoper.
FC = M*ac and FS = Mgcosteta ( not horizontal only). the next forc is not zero
when is horizontal FC = M* ac only action also, in this case the net foce is zero ( y and x ) give me some hint on this question..
the question...
Iam doing on In this laboratory, you will investigate the centripetal acceleration of a horizontally rotating object. lab report.
on this lab they asking one question ...
Would it be possible to get the string holding the rubber stopper to be PERFECTLY HORIZONTAL during this experiment...
hi mrjeffy
tx for u r advice...
i got some idea from u r post...i think I don't care abt potential energy of the rubber band ,if we assuming the arm is pulled back horizontal, when released isn't it?...so, Mgh = 1/2MV^2 is the only formula to fine velocity...rite..
I'm doing a Assignment is to conststruce a captapult that will launch a marshmallow(Large size) at target on the floor at the other end of the classroom.
I designed catapult. the rules saing the energy;; to launch the marshmallow cannot come directly from the motion of a human being.so i used...
Pls help me Calculation on distance
I'm doing a Assignment is to conststruce a captapult that will launch a marshmallow(Large size) at target on the floor at the other end of the classroom.
I designed catapult. the rules saing the energy;; to launch the marshmallow cannot come directly from...