Recent content by Confused0ne

I finally figured it out! The key is to apply logarithmic differentiation! \\ 1) \begin{equation} \frac{dp}{p} = \frac{d\gamma}{\gamma} + \frac{d\beta}{\beta} = \left(\frac{\beta^2}{1-\beta^2} +1\right)\frac{d\beta}{\beta}= \gamma^2 \frac{d\beta}{\beta} \end{equation}\\ 2) Momentum-energy...

Thanks for your reply. Since I need to express \Delta T in \Delta p, I don't see how small \Delta p approximation helps me. As soon as I try something like that (e.g. use p_0 in place of p), it all goes to hell... γ0mV0(…) doesn't bring me anywhere either...

1. Homework Statement Express the beam energy loss in the accelerator in terms of the change in the beam momentum. It is taken from one paper, where \begin{equation} \Delta T = \left( \frac{1+\gamma}{\gamma}\right) \frac{T_0 \Delta p}{p_0} \end{equation}expression is used for transition from...