Recent content by coolcat_ka

Excellent, thank you!

ok, so for part a: m=ro(x), where x=length. m1=5rx, m2=3r0 F(gravity)-F(friction)=0 so m2g-mv(m1g)=0 (9.8)(3)r0-(9.8)(5.)(0.6)r0-0 3-(5(0.6))=0 And I believe that is how I can prove that the chain starts to slide, but I wanted to makesure I had done that correctly. But I am...

Hi! I'm studying for an exam on Friday, and I'm stuck on this problem: A uniform chain of length 8.00m initially lies stretched out on a horizontal table. A. Assuming the coefficient of static friction between chain and table is 0.600, show that the chain will begin to slide off the table if...