So is this how I would do it?:
PE=mgh
PE=(4.0x10^-13)(9.8m/s/s)(1.0cm)
PE=3.92x10^-12
V= EPE/q
V=3.92x10^-12/2.4x10_18C
V= 6.8x10^23V
I don't think I did it right...
Homework Statement
HELP!
A charged particle is stationary between two horizontal charged plates. The plates are 2.0 cm apart. The particle has a mass of 4.0X10^-13 kg and a charge of 2.4 X 10^-18 C. Find the potential difference between the plates.
Homework Equations
V= EPE/q ...