Electrical Potential Difference between two plates

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Homework Help Overview

The problem involves a charged particle positioned between two horizontal charged plates, with a focus on determining the potential difference between the plates based on the particle's mass and charge.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the balance of forces acting on the particle, considering gravitational and electric forces. There are attempts to relate potential energy to the given parameters, and questions arise regarding the integration of mass into the calculations.

Discussion Status

Some participants have suggested starting with the force balance equation, while others have attempted calculations for potential energy and voltage, expressing uncertainty about the results. There is an ongoing exploration of the relationships between the variables involved.

Contextual Notes

Participants are navigating the implications of the mass and charge of the particle, as well as the distance between the plates, while adhering to homework constraints that may limit the information available for solving the problem.

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Homework Statement


HELP!
A charged particle is stationary between two horizontal charged plates. The plates are 2.0 cm apart. The particle has a mass of 4.0X10^-13 kg and a charge of 2.4 X 10^-18 C. Find the potential difference between the plates.


Homework Equations



V= EPE/q ?
...except I have no idea how to find the potential energy. Also, I have no clue how the mass given in the problem fits into an equation.

The Attempt at a Solution


I need someone to help me start this!

 
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Looks like a force-balance problem. The force of gravity (down) on the particle is balanced by an equal electric force (up). Begin with Fg = Fe and fill in the detailed formulas before solving for what you want.
 
So is this how I would do it?:
PE=mgh
PE=(4.0x10^-13)(9.8m/s/s)(1.0cm)
PE=3.92x10^-12

V= EPE/q
V=3.92x10^-12/2.4x10_18C
V= 6.8x10^23V
I don't think I did it right...
 
Fg = Fe
mg = qE
 
Thank you :]
 

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