Recent content by cormsby

wat References

Have you been reading Popper, or watching Faux Noise?

I do not think so. One of my (many) Summer jobs was at a gun shop, where I cleaned *lots* of revolver cylinders, and none looked as though they had a mere 0.004-inch (only 0.1mm, or 100nm) between chambers. Even 1.0mm (ten times as much) seems inadequate.

Thank you! From the cited "REFERENCES", I was able to locate the paper online...

A colleague (PhD Physics, no weapons experience) asked me (MA Physics, with DoD work experience) about the Betatron nuclear trigger in the early Fifties. I know it used a toroidal accelerator to produce an electron beam impacting a Beryllium target, but I don't remember (and cannot find) any...

My GF and I saw him twice at the Palms in Davis, California. I held her while she cried after learning he was killed in a car crash. He was an amazing musician.

I inherited a love for jazz from my rebellious mother. My favourite musician is the vastly-under-rated Charles Lloyd:

I inherited a love for jazz from my rebellious mother. I love Herbie Hancock, but my favourite musician is the vastly under-rated Charles Lloyd:

In one of my classes lonnng ago, a student asked why the process is called "completing the square", so I showed the class its geometric origin. From that, I showed the derivation of the quadratic formula. Many students told me this demonstration made it much more clear, so I presented it thus...

I am not a "believer". I proceed upon what I see, and what I know. I recommend everyone else do the same.

I did not see the phrase "in general", and I think you did not, either. Perhaps we should let bbsgirl explain herself, rather than speculate.

I edited a screencap of the formula (for compactness) from the ThorLabs web-page, by virtue of Fair Use bcoz U.S.Code Title 17, Section 107, blah blah blah

I did in fact read the thread, including these posts asking whether acceleration will be same for both graphs: https://www.physicsforums.com/threads/velocity-and-acceleration-graphs.1045526/post-6800175 https://www.physicsforums.com/threads/velocity-and-acceleration-graphs.1045526/post-6800187

Assuming uniform acceleration for the top graph, then solving x = ½at2 for a , using the point (20,8000) gives a=40 (units unknown). Eyeballing the bottom graph for P(10,65) and Q(25,140) then calculating slope gives a=5m/s2 , so not the same experimental data as in the top graph.

Looking at the graph with my old eyes, 40°C is at 12% atomic ratio Sn $$\frac{0.12\times 118.7}{0.12\times 118.7+0.88\times 69.72}=0.188$$ ...so 18.8% Sn by weight.