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Undergrad Parts per million of vapor above a liquor in a sealed jar
Using 893kg/m3 as the density for citral, and 1.12g/cm3 as the density for diethyl phthalate, I have: 5.866*10^-3 moles citral and 4.536*10^-2 moles diethyl phthalate in 10mL of 10% solution The mole fraction for citral is 0.1145 What do I need the moles of citral in 10grams of solution for?- costanzolab
- Post #10
- Forum: Thermodynamics
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Undergrad Parts per million of vapor above a liquor in a sealed jar
This is not a homework problem. General curiosity and tangentially related to some work we are doing with citral. Working through your questions now.- costanzolab
- Post #9
- Forum: Thermodynamics
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Undergrad Parts per million of vapor above a liquor in a sealed jar
We would like the mass concentration, and then to eventually convert this to ppm. The solution can be considered ideal. 10% is by mass (1mL pure Citral in 10 total mL of Diethyl phthalate) The air in the vial was initially at 1atm- costanzolab
- Post #7
- Forum: Thermodynamics
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Undergrad Parts per million of vapor above a liquor in a sealed jar
After getting to moles per liter how do you convert to ppm?- costanzolab
- Post #5
- Forum: Thermodynamics
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Undergrad Parts per million of vapor above a liquor in a sealed jar
Sure. Given 10mL of 10% Citral solution (dissolved in diethyl pthalate) ( vapor pressure 0.2 mm of Hg (@ 20°C)) in a closed 20mL vial, what is the concentration of the air above the liquid in parts per million.- costanzolab
- Post #4
- Forum: Thermodynamics
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Undergrad Parts per million of vapor above a liquor in a sealed jar
How would you calculate the concentration of a vapor above a liquid in a sealed jar in parts per million? Supposing that the liquid is a 10% solution of X with known vapor pressure. We've gotten to this point: 1ppm = 1mgX/ g solution 1ppm = 1mgX/1mL solution (assuming it's water and water has...- costanzolab
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- parts Per Vapor
- Replies: 13
- Forum: Thermodynamics