Recent content by courtbits

Oh OH! I got it! Now I understand! XD Thank you very much!

Would it be $$(\frac{\cos \theta}{\sin \theta})(\frac{\sin \theta}{1})$$?

Wow. x.x A typo error. I will fix it. XD

$$(\cot \theta)(\sin \theta)$$ So far I understand that you can make $$(\cot a) \implies (\frac{\cos \theta}{\sin \theta})$$ Then it would come to $$(\frac{\cos \theta}{\sin \theta})(\sin \theta)$$ I'm stuck at when making $$(\sin \theta)$$ into a fraction. The sine in between the asterisks...

Problem 3: Why do we have to square both sides?

Ok..

If $$\cos(\pi/3)= \frac{1}{2}$$, find $$\sec(\pi-\pi/3)$$ Someone really give me step-by-step explanation. I really don't know what identity to use, and no idea how to get cosine to secant. Please, it would help. I do have more questions if you help me dissect this problem. XD Thanks so much in...

1) If $$\tan(\pi/4)=1$$, find $$\cot(\pi-\pi/4)$$. 2) If $$\cot(17^{\circ}) = 3.2709$$, find $$\tan(73^{\circ})$$ 3) If $$\cot(\theta) = \frac{-9}{2}$$ with $$\theta$$ in Quadrant II, find $$\sin (\theta)$$ --------------------------------------------- I really have no idea how to solve any...

1) I have no idea what you are asking. v~v <== Dunce 2) Umm.. $${sin}^{2}\theta + {cos}^{2}\theta = 1$$ ...I think. o-o" YAAS. I figured out how to use the Latex stuff. :D

Alright. I am sort of understanding this section on my online math lesson, but I am still struggling with it. Would be gladly appreciated if someone could help me with this: If cosΘ = -4/9 with Θ in Quadrant II, find sinΘ

Wow, that did leave a bit of confusion because I had be precise with my answer. Thank you!

Yeah, I'm still completely confused. However, I will read this over and over again until I understand. Thank you very much on helping my empty brain. e.e"

so does that mean i square root sec^2(Θ) so that they eliminate and then i square root 9/5? OR am I completely off? >~>"

So what exactly is the answer, is the answer the sec^2 Θ =? to all those other identities or is the rest to solve by me? o.o" I'm a dunce I know.

[FONT=Century Gothic]If (sinΘ) = 2/3 with Θ in quadrant 1, find (secΘ) [FONT=Century Gothic]Θ = theta Completely new at trigonometric identities, would be a great help!