Recent content by Couthbaron
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Force*Time graph with respect to momentum
DonnieB, Fizznerd is right, you need the area under the curve, and you do not need calculus, as that is a trapezoid. THe area of a trapezoid is the average of the bases times the height, which is (4 + 8)seconds/2*100 N = 600 N*s. Set this to mv - mv0, and assuming v0 is zero get v final = 200 m/s.- Couthbaron
- Post #4
- Forum: Introductory Physics Homework Help
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What is the impulse of friction?
Don't forget that Impulse is NET force * time. So if you have the graph of the force of the engine vs. time, you need to subtract out kinetic friction, which is considered constant over the time. If the MR2 that kept up well with the viper was a Spyder, that is I think 137 hp and not 115 hp.- Couthbaron
- Post #8
- Forum: Introductory Physics Homework Help