Recent content by Creative-Amy

Oh ok that makes sense, thank you!:)

That is true...so no change other than a shift in negative electrons should be observed and they should both remain neutral? I just want to get this straight, whenever the y ball has been induced to be positive by the z ball(-) and x is in touch to y while this is occurring nothing should change?

Electrostatics, electrons, protons, and all that good stuff:) Homework Statement Two uncharged metal balls, X and Y, stand on glass rods, are in touch as shown to the right. A third ball Z, carrying a positive charge, is brought near the first two (closer to Y than X). Then the first two...

equations Fe=kq1q2/r^2 resultant=sqroot(x^2+y^2) q4-q1 y component ((9E9)(6.4E-19)^2)/.1^2 = 3.6864E-25 q3-q4 x component ((9E9)(6.4E-19)^2)/.1^2 = 3.6864E-25 Solve for resultant sqroot( 3.6864E-25^2+3.6864E-25^2) = 5.21E-25 = Fe equation E=Fe/q q=1.6E-19...

Homework Statement Four point charges of equal magnitude q = 6.4 X 10-19 C are placed at the corners of a square with side length a = 10 cm. Calculate the electric field at P, the center of the square, if q1 and q4 are positive and q2 and q3 are negative. (Use GUESS method.) Answer E =...